Then prove that AU (BUC)=(AUB)UC
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Assume three different sets,
A = {1,2,3} , B = {4,5,6} , C = {7,8,9}
L.H.S = (AuB)uC
= ({1,2,3}u{4,5,6}) u {7,8,9}
= {1,2,3,4,5,6} u {7,8,9}
= {1,2,3,4,5,6,7,8,9}
R.H.S = Au(BuC)
= {1,2,3} u ({4,5,6}u{7,8,9})
= {1,2,3} u {4,5,6,7,8,9})
= {1,2,3,4,5,6,7,8,9}
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