Then she sold it for 28700. Find her gain or loss percent.
5. A fruit seller bought 80 kg apples at 7 50 per kg. He sold 70% of the apples at 3 60 per kg and
remaining at 35 per kg. Find his profit or loss%
6. Feroz bought bananas at* 250 per hundred and sells them at 336 per dozen. Find the gain or loss
Answers
Answer:
pta.
nhi
shi
h
ya.nhi
Step-by-step explanation:
21.25
Answer:
Solution
Given, cost price of
1
1 kg apples
=
R
s
12.50
=Rs12.50
=> Cost price of
50
50 kg apples
=
R
s
12.50
×
50
=
R
s
625
=Rs12.50×50=Rs625
Now, Loss on
50
50 kg apples %
=
10
=10 %
=>
C
.
P
.
−
S
.
P
.
C
.
P
.
×
100
=
10
=>C.P.−S.P.C.P.×100=10
=>
625
−
S
.
P
.
625
×
100
=
10
=>625−S.P.625×100=10
=>
625
−
S
.
P
.
=
62.5.
=>625−S.P.=62.5.
=>
S
.
P
.
=
R
s
562.
5
=>S.P.=Rs562.5
=>
S
.
P
.
=>S.P. of
50
50 kg apples
=
R
s
562.
5
=Rs562.5
Now,
For, Remaining
30
30 kg apples ,
Cost price of
30
30 kg apples
=
R
s
12.50
×
30
=
R
s
375
=Rs12.50×30=Rs375
Let Selling price of
30
30 kg apples
=
R
s
x
=Rsx
So, Total CP of
80
80 kg apples
=
R
s
625
+
R
s
375
=
R
s
1000
=Rs625+Rs375=Rs1000
And Total SP of
80
80 kg apples
=
R
s
562.5
+
R
s
x
=Rs562.5+Rsx
Hence, for required Profit on the whole %
=
S
.
P
.
−
C
.
P
.
C
.
P
.
×
100
=
20
=S.P.−C.P.C.P.×100=20
562.5
+
x
−
1000
1000
×
100
=
20
562.5+x−10001000×100=20
=>
x
−
437.5
=
200
=>x−437.5=200
=>
x
=
R
s
637.5
=>x=Rs637.5
Thus, Selling price of
1
1 kg apple
=
R
s
637.5
30
=
R
s
21.25
=Rs637.530=Rs21.25