Question

Then, th
lot now
4 defective.
Find the HCF of 5404 and 4800 by Enelid's
division method
and also by factorisation Method
The num
the experir
B be the​

Answer 1

Answer:

10

Step-by-step explanation:

48250=38540×1+9710

39540=9710×3+9410

9710=9410×1+300

9410=300×31+110

300=110×2+80

110=80×1+30

80=30×2+20

20=10×2+0

Hence HCF of 38540 and 48250 is 10

Answer 2

Answer:

HCF of the given numbers are 4