Question

then what is its 7th term?
NCERT Exemplar
22.
19. If the numbers 2n - 1,3n + 2 and 6n - 1
are in AP, then find n and hence find the
numbers.
CBSE 2010
t​

Answer 1

Answer:

3n+2-(2n-1) =6n-1-(3n-2)

3n+2-2n+1 = 6n-1-3n-2

n+3 = 3n -3

6 = 2n

n=3

Answer 2

Answer:

Given: (2n−1),(3n+2) and (6n−1) are in AP.

So, difference between two consecutive terms is same.

So, (3n+2)−(2n−1)=(6n−1)−(3n+2)

(3n+2)+(3n+2)=6n−1+2n−1

6n+4=8n−2

8n−6n=4+2

or n=3

Numbers are:

2×3−1=5

3×3+2=11

6×3−1=17

Answer: (5,11,17) are required numbers.