Question

then what is the value​

Answer 1

Answer:

OddSum = (Sum of Squares of all 2n numbers) -

(Sum of squares of first n even numbers)

= 2n*(2n+1)*(2*2n + 1)/6 - 2n(n+1)(2n+1)/3

= 2n(2n+1)/6 [4n+1 - 2(n+1)]

= n(2n+1)/3 * (2n-1)

= n(2n+1)(2n-1)/3

use n(2n+1)(2n-1)/3 to find the square of first odd natural number

here n=10

put the values

we get (10)(21)(19)/3 =1330

so the option first is ur answer..

hope this will help you