Math, asked by anuj4448, 1 year ago

thenumerator of a fraction is 3 more than the denominator if the numerator and the denominator are increased by 5 the fraction becomes 10 /7 find the friction​

Answers

Answered by goelkhwahish25
4

Answer:

let the Denominator be x. then the numerator will be x+ 3

btp

x+3+5/x+5=10/7

x+8/x+5=10/7

7(x+8) =10(x+5)

7x+56=10x+50

7x-10x=50-56

-3x=-6

x=6/3

x=2

therefore numerator = 2+3=5

denominator=2

Answered by shashankbisht123
1

Answer:5/2

Step-by-step explanation:

Let denominator =x, then numerator = x+3

Fraction=x+3/x

According to ques....

Denominator=x+5

Numerator=x+3+5=x+8

(x+8)/x+5 =10/7

7x+56=10x+50

3x=6

x=2

So fraction =x+3/x=5/2

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