theoram : opposite sides and opposite angles of a parallelogram are congruent . prove
Answers
Step-by-step explanation:
Problem:--------
ABCD is a parallelogram, AD||BC and AB||DC. Prove that ∠BAD ≅ ∠DCB and that ∠ADC ≅ ∠CBA.
Strategy:-----
There are two ways to go about this. The first is to use congruent triangles to show the corresponding angles are congruent, the other is to use the Alternate Interior Angles Theorem and apply it twice.
Let’s use congruent triangles first because it requires less additional lines. Draw the diagonal BD, and we will show that ΔABD and ΔCDB are congruent.
To show these two triangles are congruent we’ll use the fact that this is a parallelogram, and as a result, the two opposite sides are parallel, and the diagonal acts as a transversal line.
The diagonal is a common side, and it is also a transversal that intersects both pairs of opposite sides of the parallelogram – creating two pairs of congruent alternate interior angles.
The triangles ΔABD and ΔCDB are congruent based on the angle-side-angle postulate, and we can show that the opposite angles of the parallelogram are congruent as corresponding angles (using the angle addition theorem for one of the pairs).
Proof:
In Parallelograms, opposite angles are congruent
(1) ABCD is a parallelogram //Given
(2) AD || BC //From the definition of a parallelogram
(3) ∠ADB ≅ ∠CBD //Alternate Interior Angles Theorem
(4) AB || DC //From the definition of a parallelogram
(5) ∠DBA ≅ ∠CDB //Alternate Interior Angles Theorem
(6) BD= BD // Common side, reflexive property of equality
(7) ΔABD ≅ ΔCDB // (3), (6), (5) Angle-Side-Angle postulate
(8) ∠BAD ≅ ∠DCB // Corresponding angles in congruent triangles (CPCTC)
(9) m∠ADC = m∠ADB+m∠BDC //angle addition theorem
(10) m∠CBA = m∠CBD+m∠DBA //angle addition theorem
(11) m∠ADC = m∠CBD+m∠BDC //(3), (7), substitution
(12) m∠ADC = m∠CBD+m∠DBA //(5), (9), substitution
(13) m∠CBA = m∠ADC //(10), (8), transitive property of equality
(14) ∠CBA ≅ ∠ADC //(11), definition of congruent angles
Given : opposite sides and opposite angles of a parallelogram are congruent
To Find : Prove
Solution:
Parallelogram , Quadrilateral in which opposite sides are parallel
Take ABCD as parallelogram
AB || CD and BC || AD
Join AC
Check Triangle
ΔABC and ΔCDA
∠BAC = ∠DCA ( ∵ AB || DC and AC is transversal , alternate interior angles)
∠BCA = ∠DAC ( ∵ AD || BC and AC is transversal , alternate interior angles)
AC ≅ AC reflexive property
Hence ΔABC ≅ ΔCDA using ASA congruence
Corresponding sides and angles of congruent triangles are congruent
AB ≅ CD and BC ≅ AD so opposite sides are congruent
∠ABC ≅ ∠CDA => ∠B ≅ ∠D opposite angles are congruent
Similarly can be shown ∠A ≅ ∠C by joining BD
QED
Hence proved
opposite sides and opposite angles of a parallelogram are congruent
Additional Info:
Diagonals of parallelogram bisect each other
Adjacent angles are supplementary. ( adds up to 180°)
Properties of angles formed by transversal line with two parallel lines :
• Corresponding angles are congruent. ( Equal in Measure)
• Alternate angles are congruent. ( Interiors & Exterior both )
• Co-Interior angles are supplementary. ( adds up to 180°)
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