Question

theorem 10.3 of class 9

Answer 1

theorem 10.3 : perpendicular from the centre on chord bisects it...............
to prove it join the end points of chord to the centre and prove the triangles congruent
and at last prove by cpct
hope this helps
expecting as brainliest

Answer 2

Hey friend,

Here's your answer,


According to this theorem,


The perpendicular from the center of a circle bisects the chord.



Proof :-


Given :-


A circle with a centre O.

AB is a chord so that AB is perpendicular to OX. (∴ AB ⊥ OX)


To prove :-


AX = BX  (∵OX bisects chord AB)


Proof :-

In Δ OAX and Δ OBX ,

Ang. OXA = Ang. OXB (Both 90° given)

OA = OB (Both radius)

OX = OX ( Common)

∴ Δ OAX ≈ Δ OBX (By RHS)

Hence,

AX = BX (cpct)

                                                Hence proved.

My teacher told this to me and I found it really helpful.



Hope this helps you !!!