Question

Theorem 3.6
.20
Solve the equation x³-9x²+14x + 24 =0 if it is given that two of its roots are in the
ratio 3:2.
o find the​

Answer 1

Answer:

×3-9x

2

+14x+24=0

Let ratio be k, then roots are 3k:2k

Here, x=−1 is a root if −1=2k then other root =−

2

3

And if −1=3k, other root =−

3

2

But roots cannot be rational here.

Now sum of root =−

a

b

=−1+2k+3k=9

5k=10

k=2