Theorem 6.1 of class 10
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After this,
Both the triangles BDE and DEC are on the same base DE and between the same parallels BC and DE.
Therefore, ar (BDE) = ar (DEC) ---(3)
From (1), (2) and (3)
AD/DB = AE/EC
Both the triangles BDE and DEC are on the same base DE and between the same parallels BC and DE.
Therefore, ar (BDE) = ar (DEC) ---(3)
From (1), (2) and (3)
AD/DB = AE/EC
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