Question

Theorem 6.7
If a perpendicular is drawn from the vertex of right angle of a right triangle to the hypotenuse then triangle on both side of the perpendicular are similar to the wall triangle and to each other.

Answer 1

Answer:

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Answer 2

Answer:

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Step-by-step explanation:

proof:

In ∆ ADB and ∆ ABC

A= A ( commom )

ADB = ABC ( each 90°)

Hence. ∆ ADB ~ ∆ ABC ( BY AA ) .……...(1)

similarly :

In ∆ BCD & ∆ ABC

C= C ( common )

BCD = ABC ( each 90°)

hence

∆ BCD ~ ∆ ABC ( by AA).……..(2)

FROM eq. (1) and (2).

∆ ADB~∆ ABC & ∆ BDC ~∆ ABC .

NOTE: If one ∆ is similar to another and

second ∆ is similar to third ∆

then first and third ∆ are similar

hence :

∆ ABD ~ ∆ BCD

PROVED