Question

Theorem 8.9 : The line segment joining the mid-points of two sides of a triangle
is parallel to the third side.
А
F
E
D
A AEF = A CDF (ASA Rule)
So,
EF = DF and BE = AE = DC (Why?)
Therefore, BCDE is a parallelogram. (Why?)
This gives EF || BC.
Fig. 8.25
B​

Answer 1

Answer:

I don't know what is your answer

Step-by-step explanation:

I think your answer is segment joining mid point of two sides of a triangle