Question

theorem- a diagonal of a parallelogram divides it into two congruent triangles​

Answer 1

Answer:

here is your solution

Answer 2

Answer:

Given,

A parallelogram ABCD with AC as its diagonal.

To prove

ΔABC =ΔADC

Proof

opposite sides of the parallelogram is parallel

so,

AB||DC and AD||BC

since AB||DC

and AC is the transversal anglBAC =DCA (alternative angle..... 1)

AD||BC

and AC is the transversal

anglDAC =BCA (alterntive angle.... 2)

In ΔABC and ΔADC

angle BAC = DCA (from.... 1)

AC=AC common

angle DAC = BCD

ΔABC=ΔADC (ASA congruent )

Hence proved.