Theorem- A perpendicular draw from the centre of a circle or it's chord bisected the chord
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given: circle with center Of
AB is the chord
OP is perpendicular to chord AB
To Prove: segment AP = segment BP
Proof : in triangle OPA and triangle OPB
angle OPA =angle OPB......OP is perpendicular to chord AB
segment OP = segment OP......common side
hypotenuse OA = hypotenuse OB.....radius of same circle
therefore, triangle OPA = triangle OPB
segment AP = segment BP ......c s c t
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