Question

Theorem : If two angles of a triangle are unequal then the side opposite to the greater angle

is greater than the side opposite to smaller angle.​

Answer 1

Given: △ABC, ∠ACB>∠ABC

To Prove: AB>AC

Construction: Make a point D on AB such that ∠ACD=∠ADC and join DC .

In △ACD,

∠ACD=∠ADC

AD=AC (Sides opposite equal angles)

But AB=AD+DB

thus, AB>AD

but AD=AC

Hence, AB>AC

Thus, sides opposite smaller angles are smaller