Question

Theoretically how many grams of magnesium is required to produce to 5.0 g of Magnesium oxide?

Answer 1

Answer:

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Explanation:

3

Answer 2

Answer:

3 grams of Magnesium are required to produce 5.0g of Magnesium oxide.

Explanation:

The reaction for the production of Magnesium dioxide will be

Mg + $O_{2}$ →  MgO

we have 5g of MgO (molar mass 40g)

number of moles of MgO = 5/40

Therefore, the number of moles of MgO = 0.125

By using the unitary method we have

1 mole of Mg requires 1 mole of MgO

0.125 Mole of MgO = 0.125mole of Mg

Where the number of moles = n

Therefore, the number of moles at

n = given mass /molar mass

0.125 = mass / molar mass

mass = $0.125* 24$

mass = 3 grams

Therefore, 3 grams of Magnesium are required to produce 5.0g of Magnesium oxide.

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