Physics, asked by HACKED, 1 year ago

TheP. E and KE of a helicopter flying horizontali, at a hight 400m are in the ratio 5:2.Then velocity of the helicopter is

Answers

Answered by vijaya2002
2

PE/KE=mgh/mv²/2

5/2=10*400/v²/2

5/2=8000/v²

5v²=16000

v²=16000/5

v=√3200

v=40√2

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