Theparallel sides of a trapezium is17 cm and 25 cm.If the
distance between them is 13
cm, find the area of that
trapezium.
*
Answers
Step-by-step explanation:
Area of trapezium ABCD = Area of ∆ ABD + Area of ∆ CBD
= 1/2 × a × h + 1/2 × b × h
= 1/2 × h × (a + b)
= 1/2 (sum of parallel sides) × (perpendicular distance between them)
✬ Area = 273 cm² ✬
Step-by-step explanation:
Given:
Measure of parallel sides of trapezium are 17 & 25 cm.
Distance between parallel sides is 13 cm.
To Find:
What is the area of trapezium ?
Solution: Let ABCD be a trapezium in which
AB = 25 cm
DC = 17 cm
DE = 13 cm
As we know that
★ Area of trapezium = 1/2(Sum of || sides)(Height)
⟹ Area = 1/2(25 + 17)(13)
⟹ 1/2 × 42 × 13
⟹ 21 × 13
⟹ 273 cm²
Hence, the area of trapezium is 273 cm².
Only one pair of opposite sides are parallel to each other.
Like other quadrilaterals, the sum of all the four angles of the trapezium is equal to 360°.