Math, asked by shaziakhan7747, 8 months ago

Theparallel sides of a trapezium is17 cm and 25 cm.If the
distance between them is 13
cm, find the area of that
trapezium.
*​

Answers

Answered by tennisenben86
1

Step-by-step explanation:

Area of trapezium ABCD = Area of ∆ ABD + Area of ∆ CBD

= 1/2 × a × h + 1/2 × b × h

= 1/2 × h × (a + b)

= 1/2 (sum of parallel sides) × (perpendicular distance between them)

Answered by ItzMahira
4

\huge\fcolorbox{black}{yellow}{Solution:-}

✬ Area = 273 cm² ✬

Step-by-step explanation:

Given:

Measure of parallel sides of trapezium are 17 & 25 cm.

Distance between parallel sides is 13 cm.

To Find:

What is the area of trapezium ?

Solution: Let ABCD be a trapezium in which

AB = 25 cm

DC = 17 cm

DE = 13 cm

As we know that

★ Area of trapezium = 1/2(Sum of || sides)(Height)

⟹ Area = 1/2(25 + 17)(13)

⟹ 1/2 × 42 × 13

⟹ 21 × 13

⟹ 273 cm²

Hence, the area of trapezium is 273 cm².

Only one pair of opposite sides are parallel to each other.

Like other quadrilaterals, the sum of all the four angles of the trapezium is equal to 360°.

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