Question

thepopulation of a town increases 10percent annually .if its present population is 60000,what will be its populationafter 2years?

Answer 1

(10% of ((10% of 60000)+60000))+(10% of 60000)+60000)=72600

Answer 2

10% of 60000 is 6000
so after one year the population will be 66000
10% of 66000 is 6600
so after the end of the second year the population will be 72600