Math, asked by vaishalispawar7, 3 months ago

Theradius of a cylinder is 5cm and its height is 10 cm .Find the curved surface area of the cylinder. ( = 3.14)

600 cm²


3140 cm²


314 cm²​

Answers

Answered by ujwalakendale18
1

Answer

314cm²

step by step explanation

Given

• Radius of cylinder = 5cm

• Height of cylinder = 10cm

To find

• Curved Surface area of the cylinder

Solution

= Radius = 5cm

= Height = 10cm

Using Formula

C. S. A of cylinder = 2πrh

Putting values

=2×22 by 7×5×10

=2200÷7

=314.2cm²

Answered by Anonymous
43

Answer:

Diagram :

\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{5\cm}}\put(9,17.5){\sf{10\cm}}\end{picture}

\begin{gathered}\end{gathered}

Given :

  • ↠ Radius of cylinder = 5 cm
  • ↠ Height of cylinder = 10 cm

\begin{gathered}\end{gathered}

To Find :

  • ↠ Curved surface area of the cylinder

\begin{gathered}\end{gathered}

Concept:

★ Here the concept of Volume of Cylinder has been used. We are given that radius of cylinder is 5 cm and height of cylinder is 10 cm.We need to find the curved surface area of the cylinder.

★ So,We'll find the curved surface area of the cylinder by insert the values in the formula.

\begin{gathered}\end{gathered}

Using Formula :

\bigstar{\underline{\boxed{\sf{CSA \: of \: cylinder =  2 \pi rh}}}}

Here

  • ↠ CSA = curved surface area
  • ↠ π = 3.14
  • ↠ r = radius
  • ↠ h = height

\begin{gathered}\end{gathered}

Solution :

\red\bigstar Here

  • ↠ π = 3.14
  • ↠ r = 5 cm
  • ↠ h = 10 cm

\begin{gathered}\end{gathered}

\red\bigstar Finding the curved surface area of cylinder

{\dashrightarrow{\pmb{\sf{CSA \: of \: cylinder =  2 \pi rh }}}}

  • Substuting the values

{\dashrightarrow{\sf{CSA \: of \: cylinder =  2  \times 3.14  \times 5 \times 10}}}

{\dashrightarrow{\sf{CSA \: of \: cylinder =  6.28 \times 50}}}

{\dashrightarrow{\sf{CSA \: of \: cylinder =   \dfrac{628}{100} \times 50}}}

{\dashrightarrow{\sf{CSA \: of \: cylinder =   \dfrac{628}{\cancel{100}} \times  \cancel{50}}}}

{\dashrightarrow{\sf{CSA \: of \: cylinder =   \dfrac{628}{2}}}}

{\dashrightarrow{\sf{CSA \: of \: cylinder =    \cancel{\dfrac{628}{2}}}}}

{\dashrightarrow{\sf{CSA \: of \: cylinder =  314 \:  {cm}^{2} }}}

{\bigstar{\underline{\boxed{\sf{CSA \: of \: cylinder =  314 \:  {cm}^{2}}}}}}

The curved surface area of cylinder is 314 cm².

\begin{gathered}\end{gathered}

Learn More :

\red\bigstar Formulas related to SA & Volume :

\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}

\begin{gathered}\end{gathered}

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