Question

There are 10 balls numbered from 1 to 10 in a box. If one of them is selected at random,
what is the probability that the number printed on the ball would be an odd number
greater that 47
(a) 0.50
(b) 0.40
(c) 0.60
(d) 0.30​

Answer 1

Question corrected:

Odd numbers greater than 4.

Answer:

Option (d), 0.30 is correct.

Step-by-step explanation:

There are 10 balls numbered 1 to 10 in the box.

For a random selection, it can be any one of the balls numbered 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

Total number of outcomes = 10

If the selected number has to be an odd number greater than 4, we require to get any one of the odd numbers 5, 7, 9 and thus the number favourable outcomes = 3

Therefore the required probability to get any odd number greater than 4 is

= number of favourable outcomes / total number of outcomes

= 3 / 10

= 0.30