Math, asked by ranawatkanishkanehs, 5 hours ago

There are 10 blocks of jaggery each of one kilogram.If one family requires two and a half kg jaggery every month.For how many families will these sufficents?​

Answers

Answered by devishri1977
5

Answer:

10 Kg will be sufficient for 4 families

Step-by-step explanation:

Weight of 10 blocks of jaggery = 10 *1 = 10 Kg

Quantity of jaggery required by one family = 2 1/2 Kg = 2.5 Kg

Number of families = Total weight ÷ quantity needed by one family

 = \dfrac{10}{2.5}=\dfrac{10*10}{2.5*10}=\dfrac{100}{25}=4

Answered by PoojaBurra
1

Given: 10 blocks of jaggery, each of one kilogram. One family requires two and a half kg jaggery every month.

To find: Number of families it will be sufficient for.  

Solution:

  • A family would require two and a half kg of jaggery every month but we have 10 blocks of jaggery and each block is equal to 1 kg.
  • So, we have a total of 10 kg of jaggery.
  • Hence, we would divide 10 kg of jaggery by two and a half kg.

       \frac{10kg}{2.5kg} = 4

  • This means that 10 blocks of jaggery could be used up by 4 families.

Therefore, it will be sufficient for four families.

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