There are 10 employees in a small business firm. From these employees, two of them have a salary of Php20,000; three of them receive Php25,000; four of them receive Php30,000; lastly the manager's salary is not given. Supposing that the average salary of the 10 employees is worth Php29,000, what is the range amount of their salaries?
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Answer:
Step-by-step explanation:
Given there are 10 employees of whom
2 of them have salary of Php 20,000
3 of them have salary of Php 25,000
4 of them have salary of Php 30,000
let the last manager's salary be 'x'
Also given that average salary of the 10 employees = Php 29,000
Average salary = (sum of all the employees salaries)/10
=(2*20,000 + 3*25,000 + 4*30,000 + x)/10
=(40,000 + 75,000 + 1,20,000 + x)/10
= 29,000
Hence ,
2,35,000 + x = 2,90,000
=> x = 55,000
Hence , Managers salary is Php 55,000.
Now among the 10 employees
least salary is Php 20,000
Highest salary is Php 55,000
Hence Range is [20,000, 55,000] and the range MOUNT OF THEIR SALARIES is 55,000-20,000
=35,000
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