there are 10 observations arrangerd in ascebding order a given below 46 ,47 ,50,52,X,X+2,60,62,63,74 the median of these odservation is 53 find the value of X. also find the mean and the mode of the data
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here is your answer hope it helps you
median=46+47+50+52+x+x+2+60+62+63+74/10
53=456+2x/10
456+2x=53×10
2x=530-456
x=74/2
x=37
value of x is 37 and the no. are 37 and 39
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median=46+47+50+52+x+x+2+60+62+63+74/10
53=456+2x/10
456+2x=53×10
2x=530-456
x=74/2
x=37
value of x is 37 and the no. are 37 and 39
pls mark it brainliest
Hirachaudhary:
Ye aapne mean method se kiya h isme median k baat k gai h
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Answer:
Step-by-step explanation:
Formula is 1/2{(n/2)th+[(n/2)+1th]}=median
For even term observation
So the total observation is 10 we put the value in this formula
1/2{(10/2)th+[(10/2)+1th]}
Then the value is 1/2 [5th +6th]
Then 5 th observation is x & 6 th is x+2
Then we put 1/2 (x+x+2)=53
We solved this we get x =52
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