There are 10-paise and 25-paise coins in a bag. If the total number of coins are 40,whose value is rupees 7.75, find the number of coins of each type.
Answers
Answered by
69
let the no. of coins of 10 paisa be x and 25 paisa be y
x+y=40 ................ ( l)
10x+25y=775 ................( ll)
multiply the equation (l) by 10
10x+10y=400 .............. (lll)
subtract (lll) from (ll) we get
10x+25y=775
-
10x+10y=400
15y=375
y=25
there are 25 coins of 25 paisa
15 coins of 10 paisa
hope it helps you
x+y=40 ................ ( l)
10x+25y=775 ................( ll)
multiply the equation (l) by 10
10x+10y=400 .............. (lll)
subtract (lll) from (ll) we get
10x+25y=775
-
10x+10y=400
15y=375
y=25
there are 25 coins of 25 paisa
15 coins of 10 paisa
hope it helps you
Answered by
22
Answer:
this is your answer
follow me
Attachments:
Similar questions