There are 10 points in three parallel planes, the first plane contain 5 points, the second plane contains 3 points and the third plane contain rest of them, then how many triangles to be formed?
Answers
Answered by
0
Answer:
2 is the correct answer
Answered by
2
Answer:
Step-by-step explanation:
In general, 3 points are needed for forming a triangle. Therefore from 10 points, we can form 10c3 triangles but out of 10 points 5 (1st line), 3 (2nd line), 2 (3rd line) points are collinear. So we have to eliminate those points and hence we subtract those colinear points from 10c3
ie, =(10c3)-(5c3)-(3c3)
=120-10-1
=109
Similar questions