There are 10 points on a straight line ab and 8 on another straight line ac none of them being point a. how many triangles can be formed with these points as vertices? option a. 680 b. 720 c. 816 d. 640
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to form a triangle we need 3 points select 2 points from the 10 points of line AC & 1 of from the 8 on AB = (10C2)*(8C1) select 2 points from the 8 points of line AB & 1 of from the 10 on AC= (8C2)*(10C1) total no. of triangles = (10C2)*(8C1)+ (8C2)*(10C1) = 640 d.640
Answered by
0
Answer:
640
Step-by-step explanation:
10C2 *8C1 + 10C1 *8C2
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