Math, asked by nhagras37, 15 days ago

there are 10 red, 8 blue, and 4 white buttons in a bag. What is the chance of taking out either a blue or a white button​

Answers

Answered by Anonymous
35

Understanding the question :-

This question, deals with probability. Probability is the prediction of how likely an event is to happen. In hindi, probability is called संभावना.

In our day to day life, we use probability very frequently. And to make our work easier, mathematicians have derived a formula for probability, and that is :-

 \qquad \: \star  \: \blue{ \underline{ \boxed{ \sf P(E) =  \frac{No.  \: of \:  trials \:  of \:  that \:  particular \:  event }{Total~number~of~trials} }}} \:  \star

Here, P (E) depicts probability of an event. Now, we will use this formula to calculate our answer.

Given Information :-

A bag, in which :-

  • Number of red buttons = 10
  • Number of blue buttons = 8
  • Number of white buttons = 4

To Find :-

Probability of taking out :-

  • White button
  • Blue button

Formula Used :-

 \qquad \: \star  \: \purple{ \underline{ \boxed{ \sf P(E) =  \frac{No.  \: of \:  trials \:  of \:  that \:  particular \:  event }{Total~number~of~trials} }}} \:  \star

Solution :-

First of all, we will calculate the total number of buttons, we get :-

 \\  \sf \dashrightarrow Total~number~of~buttons = 10 + 8 + 4 \\  \\  \\  \sf \dashrightarrow Total~number~of~buttons = 22 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\

Now, probability for taking out white button :-

  \\ \sf \dashrightarrow  P ( E) =  \dfrac{number~of~white \: buttons}{Total~number~of~buttons}  \\  \\  \\ \sf \dashrightarrow  P ( E) = \cancel  \frac{4}{22}  =  \frac{2}{11}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\

Now, probability for taking out blue button :-

  \\ \sf \dashrightarrow  P ( E) =  \dfrac{number~of \: blue \: buttons}{Total~number~of~buttons}  \\  \\  \\ \sf \dashrightarrow  P ( E) = \cancel  \frac{8}{22}  =  \frac{4}{11}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\

 \sf  \bull \: Probability ~of~taking~out=  \begin{cases} \sf1. ~Blue~button = \dfrac{4}{11}  \:  \star \\  \\  \\ \sf2. ~White~button =  \dfrac{2}{11}  \:  \star \end{cases}

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Answered by Abhinavajayankvs2009
3

Answer:

6% because

Step-by-step explanation:

10 buttons in all.

1st event: green = 2/10

With replacement, so everything is reset

2nd event: red = 3/10

Combined: 2/10 x 3/10 = 6/100 = 3/50 = 6%

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