There are 10 tickets numbered 1 to 10 are kept in a box, what is the probability of drawing a ticket which is an odd number
Answers
Step-by-step explanation:
Given :-
There are 10 tickets numbered 1 to 10 are kept in a box.
To find :-
What is the probability of drawing a ticket which is an odd number ?
Solution :-
Given that
Number of tickets = 10
Numbers on the tickets from 1, 2,...,10
Simple Space = { 1,2,3,4,5,6,7,8,9,10}
=> n(S) = 10
Total number of possible outcomes = 10
Odd numbers are 1,3,5,7,9
Total number of odd numbers = 5
Number of all favourable outcomes
n(E) = 5
Let drawing a ticket from the box randomly is an even E then
Probability of an event E = P(E)
= Number of favourable outcomes/Total number of all possible outcomes
Probability of drawing an odd numbered ticket
=> P(E) = n(E)/n(S)
=> P(E) = 5/10
=> P(E) = 1/2
Answer:-
Probability of drawing an odd numbered ticket from the box is 1/2
Used formulae:-
Probability of an event E = P(E)
= Number of favourable outcomes / Total number of all possible outcomes
Answer:
Given :-
- There are 10 tickets numbered 1 to 10 are kept in a box.
To Find :-
- What is the probability of drawing of a ticket.
Formula Used :-
Probability Formula :
Solution :-
Number of tickets = 10
There are 10 tickets numbered 1 to 10.
S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
So,
➳ Total number of outcomes = 10
Now,
There are 10 tickets.
From there, the odd number are :
1, 3, 5, 7, 9.
There are 5 favourable outcomes.
So,
➳ Number of favourable outcomes = 5
Given :
- Number of favourable outcomes = 5
- Total Number of outcomes = 10
According to the question by using the formula we get,
The probability of drawing a ticket is ½ .