Question

There are 1000 children in a school. Fora P. T. drill they have to stand in such a way that the number of rows is equal to number of columns. How many children would be left out in this arrangement?​

Answer 1

➸ Given:-

• Total No of Students in School = 1000
• Number of Rows = Number of students in a column.

☣ To Find:-

• Number of Students Left out in this arrangement.

☢ Solution:-

Let's

No of Rows be x

No of students be x

According To Sum

$→\; {x}^{2} = 1000 \\→\; x = \sqrt{1000} \\→\; x = 31.62$

Nearest Perfect Square Number is 961 which is the square of 31

→ 31×31 = 961

Number of Students Left

$→\:1000 - 961 \\→\; 39$

Number of Students Left In Arrangement

• ▣ $→\;\Large{\red{\bold{39}}}$

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Hope It Helps You ✌️

Answer 2

Answer:

➸ Given:-

Total No of Students in School = 1000

Number of Rows = Number of students in a column.

☣ To Find:-

Number of Students Left out in this arrangement.

☢ Solution:-

Let's

No of Rows be x

No of students be x

According To Sum

\begin{gathered}→\; {x}^{2} = 1000 \\→\; x = \sqrt{1000} \\→\; x = 31.62\end{gathered}→x2=1000→x=1000→x=31.62

Nearest Perfect Square Number is 961 which is the square of 31

→ 31×31 = 961

Number of Students Left

\begin{gathered}→\:1000 - 961 \\→\; 39\end{gathered}→1000−961→39

Number of Students Left In Arrangement

▣ →\;\Large{\red{\bold{39}}}→39