There are 104 class X students and 96 class IX students in a school. In a house examination the students are to be evenly seated in parallel rows such that no 2 adjacent rows are of the same class. (a) Find the maximum no. of parallel rows of each clas for the seating arrangement. (b) Find the no. of students of class IX and also of class X in a row. (c) What is the objective of the school behind such an arrangement?
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There are a total of 200 students (104 and 96).
Both 104 and 96 are divisible by 8, i.e. 104/8 = 13 and 96/8 = 12.
a). Therefore the maximum number of parallel rows would be 12+13 = 25. And, 200/8 = 25.
b). Number of students in each row would be 8.
c). The objective of the school behind such an agreement would be to easily arrange the students in rows such that no adjacent rows have students belonging to one class.
Both 104 and 96 are divisible by 8, i.e. 104/8 = 13 and 96/8 = 12.
a). Therefore the maximum number of parallel rows would be 12+13 = 25. And, 200/8 = 25.
b). Number of students in each row would be 8.
c). The objective of the school behind such an agreement would be to easily arrange the students in rows such that no adjacent rows have students belonging to one class.
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See this attachment
c) Main objective of administration behind this is to smoothly conduct the examination by keeping the check that no student can use unfair means to score marks.
This is the best possible answer
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