Math, asked by piyushjajra84, 8 months ago

There are 12 balls in a basket of which 5 are red,
4 are black and 3 blue balls. Only blue balls are
different, then number of ways to select atleast
one ball are :​

Answers

Answered by ponnadachinna020
2

Step-by-step explanation:

red balls 5

black balls 4

blue balls 3

therefore blue balls are different

Total balls are 5+4+3

=12 balls

according to the data

={ no. of favarourble outcomes / total no. of outcomes}

= 5/12. (red balls)

= 4/12

= 1/3. (black balls)

= 3/12

= 1/4. (blue balls)

may be it was helpful

Answered by priyarksynergy
0

number of  ways to select one red ball =  5/12                                                                

number of  ways to select one black  ball =  1/3

number of  ways to select one blue  ball  = 1/4

Step-by-step explanation:

Given:

Red balls = 5

Black balls = 4

Blue balls = 3

Total balls = 5+4+3

                 =12 balls

number of  ways to select one ball are ={ no. of favorable outcomes /total                                          no. of outcomes}

number of  ways to select one red ball =  5/12                                                                

number of  ways to select one black  ball =   4/12    

                                                                      = 1/3

number of  ways to select one blue  ball =   3/12    

                                                                    = 1/4

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