Question

There are 12 bead in a box, some are white and some are black. The probability of drawing a white bead is 1/3.


a. How many white beads and black beads are there in the box?


b. If we take 3 black beads from the box, what is the probability of drawing a white bead?


c. What is the probability of drawing a black bead if we put three more black in the box?


!!!!!!!answer it urgent!!!!!​

Answer 1

Answer:

There are four white breads in the box

Step-by-step explanation:

let number of white breads is x

x/12 =1/3

x = 1/3×12

x = 4

Answer 2

Step-by-step explanation:

$a)white \: beads = \frac{1}{3} of12 \\ = \frac{1}{3} \times 12 \\ = 4 \\ black \: beads = 12 - 4 \\ = 8 \\ \\ b)black \: beads \: left \: = 8 - 3 = 5 \\ total \: beads \: in \: box = 4 + 5 = 9 \\ p(white \: bead) = \frac{4}{9} \\ \\ c)black \: beads \: left \: = 8 + 3 = 11 \\ total \: beads \: in \: box = 4 + 11= 15\\ p(black \: bead) = \frac{11}{15}$