Question

There are 12 boys and 18 girls in a line. If one student is chosen in random, find the probability that the
elected student is a girl.​

Answer 1

Step-by-step explanation:

Number of ways of selecting 2 students from 30 students = 30C2 ways

= ( 30 x 29 )/2

= 15 x 29 ways

Number of ways of selecting 2 girls from 12 girls = 12C2 ways

= 12 x 11 / 2

= 6 x 11

Thus, probability that both selected students are girls

= ( 6 x 11 ) / ( 15 x 29 )

= 22 / 145

=6.9

Answer 2

Answer:

The probability is $\frac{3}{5}$.

Step-by-step explanation:

It is given that there are twelve boys and eighteen girls in a line.

One girl has to be chosen randomly.

We need to determine the probability that elected student is a girl.

Probability is defined as the ratio of number of favorable outcomes to total outcomes.

Here

Favorable outcomes are $18$

Total outcomes are $12+18=30$

Hence, as per the definition of probability,

Probability $=\frac{18}{30} =\frac{3}{5}$

#SPJ2