There are 12 white, 7 red and 11 black balls in a box. Again there are 7 white, 10 red and 13 black balls in another box. Now if you pick up one ball from each of the box independently what will be the probability of getting –
i) Two white balls?
ii) Two red balls?
iii) Two black balls?
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Step-by-step explanation:
total balls in first box is 12+7+11 = 30
total balls in second box is 7+10+13 = 30
I) two White balls = 12/30 × 7/30
ii) two red balls = 7/30 × 10/30
iii) two black balls = 11/30 × 13/30
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