Question

There are 120 cars in a multistorey car park.Given that 30% of them are blue, Find the number of cars which are not blue.​

Answer 1

$\boxed{\bf{\red{Answer:-84}}}$

$\huge\mathbb{SOLUTION:-}$

Given:-

• .Total number of car =120

• 30%are blue

• .and we have to find how many cars which are not in blue colour

Now 1st find the 30%of 120

$\sf\implies 30\%of 120\\ \\ \sf\implies \frac{3\cancel0}{1\cancel{00}}\times 12\cancel{0}\\ \\ \sf\implies 3\times 12=36$

30% of 120 is 36

so the number of blue cars is 36

• Now we have to find the number of cars which are not blue

$\boxed{\sf{\blue{No.\:of\:non\:blue\:car=Total\:No.\:of\:car -No. \:of\:blue\:car}}}$

$\sf\implies No. \:of\:non\:blue\:car= 120-36\\ \\ \sf\implies Non\; blue \:car= 84$

$\boxed{\bf{Number\:of\:non\:blue\:car=84}}$

Answer 2

Answer:

$\small\underline\textsf{84 \:Non\: blue \:car }$

$\small\underline\textsf{36\: blue \:color }$

$\tt{Given}\begin{cases}\tt{total \:car =120} \\ \tt{blue car = 93\%} \\\tt{Non \:blue\: car=?}\end{cases}$

$\large\underline\textsf{To Find }$

$\small\textsf{ 30\%of\: 120}$

$\huge\underline\textsf{Explantion:- }$

$\implies\bf \frac{3\cancel0}{1\cancel0\cancel0} ×12\cancel0$

$\implies\bf3 \times 12 = 36$

$\implies\large\textsf{the \:number \:of\: blue \:car\: 36}$

$\rule{300}{2}$

$\implies\small\underline\textsf{Now\: we\: have \:to \:find}$

$\implies\boxed{\bf blue\: car = no.of \: car - non \: blue \: colour \: car}$

$\implies\bf no. \: the \: non \: blue \: car = 120 - 36$

$\implies\bf non \: blue \: car = 84$