Math, asked by Tiku040781, 1 month ago

There are 1200 people in a city. Out of them 48% people speak Hindi. 72 people speak Hindi and English. 9% people speak English and Tamil. 30% people speak Tamil. 36 people speak all three languages. 54% people speak English. Each person speak at least one language from above three.​

Answers

Answered by sreyar271
0

Answer:

Let A→ Set of people who speak English.

B→ Set of people who speak French.

A−B→ Set of people who speak English and not French.

B−A→ Set of people who speak French and not English.

A∩B→ Set of people who speak both English and French.

Given

n(A)=72n(B)=43n(A∪B)=100

Now,

n(A∪B)=n(A)+n(B)−n(A∪B)

=72+43−100

=15

∴ Number of persons who speak both English and French are 15

n(A)=n(A−B)+n(A∩B)

⇒n(A−B)=n(A)−n(A∩B)

=72−15

=57

And

⇒n(B−A)=n(B)−n(A∩B)

=43−15

=28

∴ Number of people speaking English only are 57.

and Number of people speaking French only are 28.

Answered by lc7804
0

Answer:

I don't now the answer it can be anything

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