Question

There are 13 rows in a classroom. The laughing gas is released from the 1st row and tear gas from the last row. The students sitting in 10th row lagh and weep. Find molar mass of tear gas

Answer 1

I am assuming laughing gas is N2O.

M.wt=14+14+16=44

We know,

rate is inversely proportional to square root of mwt. (Graham's Law of Diffusion)

Thus,

r(laughing)/r(tear)=(x/44)^0.5

It is given that,

r(laughing)=k*10

r(tear)=k*3

(acc. to what is given in the passage)

Use this and calculate x.

PS-Please mark this as the brainliest answer)