Question

there are 143 boys and 364 girls students in a School principal wants to divide them in section such that a section can have only boys or girls if all sections should have same number of students and principal wants to have as fewer section as possible find the number of sections as possible find the number of sections in the School ​

Answer 1

Step-by-step explanation:

Let 'x' be the total number of sections. 

Let 'x' be the total number of sections. 'y' is the number of boys in a section.

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y114 = x×z

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y114 = x×zDividing both the equations we get:-

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y114 = x×zDividing both the equations we get:-1920=zy

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y114 = x×zDividing both the equations we get:-1920=zyThis means that we can let 'y' be equal to 20 and 'z' be equal to 19 (in lowest fraction)

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y114 = x×zDividing both the equations we get:-1920=zyThis means that we can let 'y' be equal to 20 and 'z' be equal to 19 (in lowest fraction)Hence we get:

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y114 = x×zDividing both the equations we get:-1920=zyThis means that we can let 'y' be equal to 20 and 'z' be equal to 19 (in lowest fraction)Hence we get:x=20120=6

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y114 = x×zDividing both the equations we get:-1920=zyThis means that we can let 'y' be equal to 20 and 'z' be equal to 19 (in lowest fraction)Hence we get:x=20120=6Thus there are 6 section

just take it as example and try to do that some ur self I hope this would help u pls like it and mark as brainlist pls

Answer 2

Let 'x' be the total number of sections. 

Let 'x' be the total number of sections. 'y' is the number of boys in a section.

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y114 = x×z

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y114 = x×zDividing both the equations we get:-

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y114 = x×zDividing both the equations we get:-1920=zy

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y114 = x×zDividing both the equations we get:-1920=zyThis means that we can let 'y' be equal to 20 and 'z' be equal to 19 (in lowest fraction)

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y114 = x×zDividing both the equations we get:-1920=zyThis means that we can let 'y' be equal to 20 and 'z' be equal to 19 (in lowest fraction)Hence we get:

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y114 = x×zDividing both the equations we get:-1920=zyThis means that we can let 'y' be equal to 20 and 'z' be equal to 19 (in lowest fraction)Hence we get:x=20120=6

Let 'x' be the total number of sections. 'y' is the number of boys in a section.'z' is the number of girls in a section.Now 120 = x×y114 = x×z

Dividing both the equations we get :-1920 =zy This means that we can let 'y' be equal to 20 and 'z' be equal to 19 (in lowest fraction)Hence we get:x=20120=6.Thus there are 6 section

PLEASE MARK BRAINIEST