Question

There are 146 bubls in a box
in which 132 are goods and
remaining are defective. A bulb is.
drawn randomly and bulb is good
which is not replace a in a box
and another bulb is drawn. And
find the probability that bulb is defective.​

Answer 1

Answer:

the probability = no of fav. outcomes/total no of outcomes.

here 1 good bulb is first removed then the no of good bulbs left over are 131

and total bulbs are 145

total no of defective bulbs remain same here...

146-132 = 14

then P ď = 14/145 answer...