Question

There are 15 boys and 20 girls in a class. What is the probability that-
i) a boy secures 1st position in class.
ii) a girl secures 1st position in class.​

Answer 1

Answer:

20/35 = 4/7

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Step-by-step explanation:

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Answer 2

Given ,

• Total boys ➝ 15
• Total girls ➝ 20

To find ;

• Probability of a boy secures 1st position in class.

• Probability of a girl secures 1st position in class.

$\large\red\maltese$ The empirical probability P(E) of an event E happening is given by ➝

${\boxed{\rm{\green{P(E) =\frac{Numbers \: of \: trials \: in \: which \: the \: event \: happened}{Total \: number \: of \: trails}}}}}$

Solution ➝

Total no. of outcomes ⟹ Total no. of girls + Total no. of boys

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$ ⟹ 20 + 15

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$ ⟹ 35

i) Probability of a boy secures 1st position in class

${\boxed{\rm{\red{P(E) =\frac{Numbers \: of \: trials \: in \: which \: the \: event \: happened}{Total \: number \: of \: trails}}}}}$

${\rm{\green{P(E) = \frac{\cancel{15}^{3}}{\cancel{35}^{7}}=\frac{3}{7}}}}$

ii) Probability of a girl secures 1st position in class

${\rm{\green{P(E) = \frac{\cancel{20}^{4}}{\cancel{35}^{7}}=\frac{4}{7}}}}$

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$\large \fbox \purple {Hope \: it \: helps \: you}$