Question

there are 15 terms in an AP its first term is 5 and their sum is 390.the middle term is

Answer 1

No. of terms=15

a=5

sn=390
$s15 = \frac{15}{2} (2 \times 5 + 14d) \\ 390 = 75 + 105d \\ d = \frac{315}{105} \\ d = 3 \\ middle \: term \: will \: be \: 8th \: so \\ a8 = a + 7d \\ a8 = 5 + 7 \times 3 \\ a8 = 26$
middle term is 26

Answer 2

Answer:

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