There are 15 tickets bearing the numbers 1 to 15 in a bag. One ticket is draw at random from the bag. Complete the following activity to find the probability of event 4, that the ticket drawn bears number multiple of 1
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12456())+2++2)2910101)1)2))191929199191919191
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Answer:
Sample space = 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15
Probability of 4 = E
Favourable outcomes=14(1,2,3,5,6,7,8,9,10,11,12,13,14,15)
tatal possible outcomes= 15.
P(4) = P(E) = Favourable outcomes /totaloutcomes
= 14/15
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