Question

there are 15 tickets bearing the numbers 1 to 15 in a bag one ticket is drawn at random from the bag to find the probability of event A that the ticket drawn bears a number multiple of 5

Answer 1

total outcome = 15
no of multiple of 5 = 3 (5,10,15)
P(E) = no of favourable outcome/ total outcome
= 3/15
= 1/5

Answer 2

Answer:(s)={1,2,3...15}

N(s)=15

N(A)=3

P(a)=n(a)÷p(a)=3÷15=1÷5