There are 15 tickets in a box, each bearing one of the numbers from 1 to 15. One ticket is drawn at random from the box. Find the probability of event that the ticket drawn -
(1) shows an even number.
(2) shows a number which is a multiple of 5.
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Answer:
7/15 - showing even number
1/5 - showing a multiple of 5
Step-by-step explanation:
Total tickets = 15
Tickets with even number = 7 ( 2 , 4 , 6 , 8 , 10 , 12 , 14)
Tickets multiple of 5 = 3 ( 5 , 10 , 15)
Probability of showing even number = 7/15
Probability of showing a number multiple of 5 = 3/15 = 1/5
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