There are 156, 208, and 260 students in groups A,B and C respectively. Buses are to be hired to take them for a trip. Find maximum buses to be hired if same number and students are accomodated in each bus
Answers
Answer:
maximum number of buses = 3
And
maximum number of students carry in each bus = 208
Answer:
18 buses
Step-by-step explanation:
The number of buses will be minimum if each bus accomodated maximum number of students.
The no of students in each bus must be HCF of 156,208 and 260students.
Prime factorisation of 156,208,260 are :
156= 2^2 x 3 x 13
208= 2^4 x 13
260= 2^2 x 5 x 13
HCF of 156,208 and 260 = 2^2 x 13 = 52
In each bus 52 students can be accomodated
minimum no of uses required = Total no of students/52
= 156+208+260/52
= 624/52
= 18 Buses
18 buses will be hired if the same number of students be accomodated in each bus.
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