Question

There are 156, 208 and 260 students in three groups. Buses are hired to take them to the Zoo. Find the minimum number of buses to be hired, if students of each group are accommodate separately and the same number of students should be accommodated in each bus.
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Answer 1

$\huge \mathfrak \purple{hello \: friend}$

First, we need to calculate the HCF of 156,208 and 260,

Prime factorisation of:

156=2×2×3×13

208=2×2×2×2×13

260=2×2×5×13

Here, 13 and 2² are the common factors, hence

HCF(156,208,260)=13×2×2=52

Therefore,

Maximum number of students that can be seated in a bus=52

Now,

Total number of students=156+208+260=624

Number of buses required=624÷52=12

Answer: 12 buses

Answer 2

HeRe Is Your Ans

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➡HCF Of 156,208 and 260 is 52

➡Total Students = 156 + 208 + 260 = 624

➡Number Of Buses = Total Students / HCF Of 156,208 and 260

➡Number Of Buses = 624 / 52

➡Number Of Buses = 12

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