Question

There are 2 bags a and

b. Bag a contain 6 red flowers and 3 pink flowers where as bag b contains 2 red flowers and 7 pink flowers. One flower is chosen from bag a randomly what is the probability that the flower chosen is pink?

Answer 1

Bag A 6 red + 3 pink

Pa(pink flower)= favorable outcomes/total no. of outcomes from bag A

Probability of picking 1 pink from bag A is 3/9

Answer 2

Answer:

$\frac{5}{9}$

Step-by-step explanation:

Bag A

Red flowers = 6

Pink flowers = 3

Bag B

Red flowers = 2

Pink flowers = 7

Total flowers in both bags = 6+3+2+7=18

Total pink flowers = 3+7=10

The probability that the flower chosen is pink = $\frac{\text{No. of pink flowers}}{\text{Total no. of flowers}}$

                                                                          = $\frac{10}{18}$

                                                                          = $\frac{5}{9}$

Hence The probability that the flower chosen is pink is  $\frac{5}{9}$