there are 2 black balls an 5 red balls 3 balls are taken out what is the probability of 2 balls being red
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it must be 2/7
hope this helps u
hope this helps u
Answered by
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consider taking out 2 balls from group of 5 red balls and rest 1 ball from group of 1 black ball.
now, by permutation and combination
=(5C2×2C1)/7C3
=20/35
=4/7
now, by permutation and combination
=(5C2×2C1)/7C3
=20/35
=4/7
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