Question

There are 2 boxes. First contains 6 red, 5 green and 9 white balls whereas second contains 10 red, 4 green and 6 white balls. If 1 ball is selected at random from one of the boxes, then probability of getting green ball will be

Answer 1

Probability of selecting boxes is ½

P(Selecting 1 ball from box1) = 1/20

P(selecting 1green ball from box1)= 1/5

P(selecting 1 ball from box2)= 1/20

P(selecting 1green ball from box2)= 1/4

Apply Baye's Theoem to get the answer!!