There are 2 boxes. First contains 6 red, 5 green and 9 white balls whereas second contains 10 red, 4 green and 6 white balls. If 1 ball is selected at random from one of the boxes, then probability of getting green ball will be
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Probability of selecting boxes is ½
P(Selecting 1 ball from box1) = 1/20
P(selecting 1green ball from box1)= 1/5
P(selecting 1 ball from box2)= 1/20
P(selecting 1green ball from box2)= 1/4
Apply Baye's Theoem to get the answer!!
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